summaryrefslogtreecommitdiffstats
path: root/mm/slub.c
diff options
context:
space:
mode:
authorJoonsoo Kim <js1304@gmail.com>2012-08-16 00:02:40 +0900
committerPekka Enberg <penberg@kernel.org>2012-10-19 10:19:24 +0300
commit837d678dc264c797c16f81cf56f615f7544891c1 (patch)
tree9ed759efc6bb0e404a6e4faf576f50b4641011a3 /mm/slub.c
parentddffeb8c4d0331609ef2581d84de4d763607bd37 (diff)
downloadlinux-837d678dc264c797c16f81cf56f615f7544891c1.tar.bz2
slub: remove one code path and reduce lock contention in __slab_free()
When we try to free object, there is some of case that we need to take a node lock. This is the necessary step for preventing a race. After taking a lock, then we try to cmpxchg_double_slab(). But, there is a possible scenario that cmpxchg_double_slab() is failed with taking a lock. Following example explains it. CPU A CPU B need lock ... need lock ... lock!! lock..but spin free success spin... unlock lock!! free fail In this case, retry with taking a lock is occured in CPU A. I think that in this case for CPU A, "release a lock first, and re-take a lock if necessary" is preferable way. There are two reasons for this. First, this makes __slab_free()'s logic somehow simple. With this patch, 'was_frozen = 1' is "always" handled without taking a lock. So we can remove one code path. Second, it may reduce lock contention. When we do retrying, status of slab is already changed, so we don't need a lock anymore in almost every case. "release a lock first, and re-take a lock if necessary" policy is helpful to this. Signed-off-by: Joonsoo Kim <js1304@gmail.com> Acked-by: Christoph Lameter <cl@linux.com> Signed-off-by: Pekka Enberg <penberg@kernel.org>
Diffstat (limited to 'mm/slub.c')
-rw-r--r--mm/slub.c34
1 files changed, 14 insertions, 20 deletions
diff --git a/mm/slub.c b/mm/slub.c
index a0d698467f70..e7aec2001ae5 100644
--- a/mm/slub.c
+++ b/mm/slub.c
@@ -2459,7 +2459,6 @@ static void __slab_free(struct kmem_cache *s, struct page *page,
void *prior;
void **object = (void *)x;
int was_frozen;
- int inuse;
struct page new;
unsigned long counters;
struct kmem_cache_node *n = NULL;
@@ -2472,13 +2471,17 @@ static void __slab_free(struct kmem_cache *s, struct page *page,
return;
do {
+ if (unlikely(n)) {
+ spin_unlock_irqrestore(&n->list_lock, flags);
+ n = NULL;
+ }
prior = page->freelist;
counters = page->counters;
set_freepointer(s, object, prior);
new.counters = counters;
was_frozen = new.frozen;
new.inuse--;
- if ((!new.inuse || !prior) && !was_frozen && !n) {
+ if ((!new.inuse || !prior) && !was_frozen) {
if (!kmem_cache_debug(s) && !prior)
@@ -2503,7 +2506,6 @@ static void __slab_free(struct kmem_cache *s, struct page *page,
}
}
- inuse = new.inuse;
} while (!cmpxchg_double_slab(s, page,
prior, counters,
@@ -2529,25 +2531,17 @@ static void __slab_free(struct kmem_cache *s, struct page *page,
return;
}
+ if (unlikely(!new.inuse && n->nr_partial > s->min_partial))
+ goto slab_empty;
+
/*
- * was_frozen may have been set after we acquired the list_lock in
- * an earlier loop. So we need to check it here again.
+ * Objects left in the slab. If it was not on the partial list before
+ * then add it.
*/
- if (was_frozen)
- stat(s, FREE_FROZEN);
- else {
- if (unlikely(!inuse && n->nr_partial > s->min_partial))
- goto slab_empty;
-
- /*
- * Objects left in the slab. If it was not on the partial list before
- * then add it.
- */
- if (unlikely(!prior)) {
- remove_full(s, page);
- add_partial(n, page, DEACTIVATE_TO_TAIL);
- stat(s, FREE_ADD_PARTIAL);
- }
+ if (kmem_cache_debug(s) && unlikely(!prior)) {
+ remove_full(s, page);
+ add_partial(n, page, DEACTIVATE_TO_TAIL);
+ stat(s, FREE_ADD_PARTIAL);
}
spin_unlock_irqrestore(&n->list_lock, flags);
return;