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authorRasmus Villemoes <linux@rasmusvillemoes.dk>2015-11-04 15:52:28 -0600
committerMartin K. Petersen <martin.petersen@oracle.com>2015-11-09 12:39:27 -0500
commit1faf072c0e3ab0bc41fc1d343883dac704b82946 (patch)
treee1ddaa85e1cd51f2ee6572282adbe6cba9fcfa31 /mm/oom_kill.c
parent7c59a0d46125d8c47c840e874d2cc9dd082afdf7 (diff)
downloadlinux-1faf072c0e3ab0bc41fc1d343883dac704b82946.tar.bz2
hpsa: fix multiple issues in path_info_show
path_info_show() seems to be broken in multiple ways. First, there's 817 return snprintf(buf, output_len+1, "%s%s%s%s%s%s%s%s", 818 path[0], path[1], path[2], path[3], 819 path[4], path[5], path[6], path[7]); so hopefully output_len contains the combined length of the eight strings. Otherwise, snprintf will stop copying to the output buffer, but still end up reporting that combined length - which in turn would result in user-space getting a bunch of useless nul bytes (thankfully the upper sysfs layer seems to clear the output buffer before passing it to the various ->show routines). But we have 767 output_len = snprintf(path[i], 768 PATH_STRING_LEN, "[%d:%d:%d:%d] %20.20s ", 769 h->scsi_host->host_no, 770 hdev->bus, hdev->target, hdev->lun, 771 scsi_device_type(hdev->devtype)); so output_len at best contains the length of the last string printed. Inside the loop, we then otherwise add to output_len. By magic, we still have PATH_STRING_LEN available every time... This wouldn't really be a problem if the bean-counting has been done properly and each line actually does fit in 50 bytes, and maybe it does, but I don't immediately see why. Suppose we end up taking this branch: 802 output_len += snprintf(path[i] + output_len, 803 PATH_STRING_LEN, 804 "BOX: %hhu BAY: %hhu %s\n", 805 box, bay, active); An optimistic estimate says this uses strlen("BOX: 1 BAY: 2 Active\n") which is 21. Now add the 20 bytes guaranteed by the %20.20s and then some for the rest of that format string, and we're easily over 50 bytes. I don't think we can get over 100 bytes even being pessimistic, so this just means we'll scribble into the next path[i+1] and maybe get that overwritten later, leading to some garbled output (in fact, since we'd overwrite the previous string's 0-terminator, we could end up with one very long string and then print various suffixes of that, leading to much more than 400 bytes of output). Except of course when we're filling path[7], where overrunning it means writing random stuff to the kernel stack, which is usually a lot of fun. We can fix all of that and get rid of the 400 byte stack buffer by simply writing directly to the given output buffer, which the upper layer guarantees is at least PAGE_SIZE. s[c]nprintf doesn't care where it is writing to, so this doesn't make the spin lock hold time any longer. Using scnprintf ensures that output_len always represents the number of bytes actually written to the buffer, so we'll report the proper amount to the upper layer. Reviewed-by: Hannes Reinecke <hare@suse.de> Reviewed-by: Tomas Henzl <thenzl@redhat.com> Reviewed-by: Matthew R. Ochs <mrochs@linux.vnet.ibm.com> Signed-off-by: Rasmus Villemoes <linux@rasmusvillemoes.dk> Signed-off-by: Don Brace <don.brace@pmcs.com> Signed-off-by: Martin K. Petersen <martin.petersen@oracle.com>
Diffstat (limited to 'mm/oom_kill.c')
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