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authorHeiko Carstens <heiko.carstens@de.ibm.com>2015-08-17 07:56:20 +0200
committerMartin Schwidefsky <schwidefsky@de.ibm.com>2015-08-19 10:40:17 +0200
commite619cd3d618672bea8602d682ea63b42a1faf1bc (patch)
treeeb14d81bb7c0e8fdc8a550334c61860c73c0ddf4 /drivers/s390/crypto
parent89b1145e93771d727645c96e323539c029b63f1c (diff)
downloadlinux-e619cd3d618672bea8602d682ea63b42a1faf1bc.tar.bz2
s390/hmcdrv: fix interrupt registration
The z/VM driver sets bit "63-22" in control register zero to one in order to enable the CP Service interrupt (0x2603). However the irq subclass mask that normally corresponds to the CP Service interrupt is "63-54" (== "63-22-32"). So it looks like the author read the documentation with the 32 bit sized cr0 register bit positions (== 22), but didn't realize that bit numbers change, if applied to a 64 bit register (== 54) due to the numbering scheme. Also use irq_subclass_register() instead if ctl_set_bit() since multiple services depend on the service signal subclass mask, which is the correct bit. This also explains why nobody noticed the bug, since the bit is always enabled anyway (e.g. pfault). Signed-off-by: Heiko Carstens <heiko.carstens@de.ibm.com> Reviewed-by: Hendrik Brueckner <brueckner@linux.vnet.ibm.com> Acked-by: Martin Schwidefsky <schwidefsky@de.ibm.com> Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com>
Diffstat (limited to 'drivers/s390/crypto')
0 files changed, 0 insertions, 0 deletions