debugfs: make debugfs_create_u32_array() return void

The single user of debugfs_create_u32_array() does not care about the
return value of it, so make it return void as there is no need to do
anything with the return value.

Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>

1 files changed, 1 insertions, 1 deletions

diff --git a/Documentation/filesystems/debugfs.txt b/Documentation/filesystems/debugfs.txt
index 4a0a9c3f4af6..9e27c843d00e 100644
--- a/Documentation/filesystems/debugfs.txt
+++ b/Documentation/filesystems/debugfs.txt
@@ -169,7 +169,7 @@ byte offsets over a base for the register block.
 
 If you want to dump an u32 array in debugfs, you can create file with:
 
-    struct dentry *debugfs_create_u32_array(const char *name, umode_t mode,
+    void debugfs_create_u32_array(const char *name, umode_t mode,
 			struct dentry *parent,
 			u32 *array, u32 elements);