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authorLinus Torvalds <torvalds@linux-foundation.org>2022-03-21 14:09:34 -0700
committerLinus Torvalds <torvalds@linux-foundation.org>2022-03-21 14:09:34 -0700
commitd2eb5500f1d916c9b0815cdc63c48a6d615532cc (patch)
treea68e5a8f7da4812ad8624d1f8154f95a9d8ae86e
parent35dc0352bb6cf611f01dba41b722fd2b9a819204 (diff)
parente2b665f612ca2ddc61c3d54817a3a780aee6b251 (diff)
downloadlinux-d2eb5500f1d916c9b0815cdc63c48a6d615532cc.tar.bz2
Merge tag 'lkmm.2022.03.13a' of git://git.kernel.org/pub/scm/linux/kernel/git/paulmck/linux-rcu
Pull memory model doc update from Paul McKenney: "An improved explanation of syntactic and semantic dependencies from Alan Stern" * tag 'lkmm.2022.03.13a' of git://git.kernel.org/pub/scm/linux/kernel/git/paulmck/linux-rcu: tools/memory-model: Explain syntactic and semantic dependencies
-rw-r--r--tools/memory-model/Documentation/explanation.txt51
1 files changed, 51 insertions, 0 deletions
diff --git a/tools/memory-model/Documentation/explanation.txt b/tools/memory-model/Documentation/explanation.txt
index 394ee57d58f2..ee819a402b69 100644
--- a/tools/memory-model/Documentation/explanation.txt
+++ b/tools/memory-model/Documentation/explanation.txt
@@ -485,6 +485,57 @@ have R ->po X. It wouldn't make sense for a computation to depend
somehow on a value that doesn't get loaded from shared memory until
later in the code!
+Here's a trick question: When is a dependency not a dependency? Answer:
+When it is purely syntactic rather than semantic. We say a dependency
+between two accesses is purely syntactic if the second access doesn't
+actually depend on the result of the first. Here is a trivial example:
+
+ r1 = READ_ONCE(x);
+ WRITE_ONCE(y, r1 * 0);
+
+There appears to be a data dependency from the load of x to the store
+of y, since the value to be stored is computed from the value that was
+loaded. But in fact, the value stored does not really depend on
+anything since it will always be 0. Thus the data dependency is only
+syntactic (it appears to exist in the code) but not semantic (the
+second access will always be the same, regardless of the value of the
+first access). Given code like this, a compiler could simply discard
+the value returned by the load from x, which would certainly destroy
+any dependency. (The compiler is not permitted to eliminate entirely
+the load generated for a READ_ONCE() -- that's one of the nice
+properties of READ_ONCE() -- but it is allowed to ignore the load's
+value.)
+
+It's natural to object that no one in their right mind would write
+code like the above. However, macro expansions can easily give rise
+to this sort of thing, in ways that often are not apparent to the
+programmer.
+
+Another mechanism that can lead to purely syntactic dependencies is
+related to the notion of "undefined behavior". Certain program
+behaviors are called "undefined" in the C language specification,
+which means that when they occur there are no guarantees at all about
+the outcome. Consider the following example:
+
+ int a[1];
+ int i;
+
+ r1 = READ_ONCE(i);
+ r2 = READ_ONCE(a[r1]);
+
+Access beyond the end or before the beginning of an array is one kind
+of undefined behavior. Therefore the compiler doesn't have to worry
+about what will happen if r1 is nonzero, and it can assume that r1
+will always be zero regardless of the value actually loaded from i.
+(If the assumption turns out to be wrong the resulting behavior will
+be undefined anyway, so the compiler doesn't care!) Thus the value
+from the load can be discarded, breaking the address dependency.
+
+The LKMM is unaware that purely syntactic dependencies are different
+from semantic dependencies and therefore mistakenly predicts that the
+accesses in the two examples above will be ordered. This is another
+example of how the compiler can undermine the memory model. Be warned.
+
THE READS-FROM RELATION: rf, rfi, and rfe
-----------------------------------------